34ad5b457d
This is because we re-use BlendingState for our internal drawing (e.g. RasterFont) and for these shaders, we can't assume the presence of a second color output. |
||
---|---|---|
.. | ||
D3D | ||
D3D12 | ||
Null | ||
OGL | ||
Software | ||
Vulkan | ||
CMakeLists.txt |