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JitArm64: Discard top 32 bits in slwx result 

srwx would like to be able to assume that the top 32 bits
are zero, and cmpl is already doing so.
This commit is contained in:
JosJuice 2021-06-05 23:15:08 +02:00
parent 2f8c9a7735
commit 86de3df072
1 changed files with 3 additions and 10 deletions
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13
Source/Core/Core/PowerPC/JitArm64/JitArm64_Integer.cpp
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@ -1451,15 +1451,12 @@ void JitArm64::slwx(UGeckoInstruction inst)
{
gpr.BindToRegister(a, a == b || a == s);
// PowerPC any shift in the 32-63 register range results in zero
// Since it has 32bit registers
// AArch64 it will use a mask of the register size for determining what shift amount
// So if we use a 64bit so the bits will end up in the high 32bits, and
// Later instructions will just eat high 32bits since it'll run 32bit operations for everything.
// On PowerPC, shifting a 32-bit register by an amount from 32 to 63 results in 0.
// We emulate this by using a 64-bit operation and then discarding the top 32 bits.
LSLV(EncodeRegTo64(gpr.R(a)), EncodeRegTo64(gpr.R(s)), EncodeRegTo64(gpr.R(b)));
if (inst.Rc)
ComputeRC0(gpr.R(a));
MOV(gpr.R(a), gpr.R(a));
}
}
@ -1499,10 +1496,6 @@ void JitArm64::srwx(UGeckoInstruction inst)
{
gpr.BindToRegister(a, a == b || a == s);
// wipe upper bits. TODO: get rid of it, but then no instruction is allowed to emit some higher
// bits.
MOV(gpr.R(s), gpr.R(s));
LSRV(EncodeRegTo64(gpr.R(a)), EncodeRegTo64(gpr.R(s)), EncodeRegTo64(gpr.R(b)));
if (inst.Rc)