Simplify log queue clearing.

Simply just keep popping the queue until it's empty. No point in using a for loop for this.

Combined some if statements too.
This commit is contained in:
Lioncash 2014-03-16 19:56:57 -04:00
parent fe37a772a4
commit 5edce0eeb6
1 changed files with 38 additions and 41 deletions

View File

@ -205,8 +205,7 @@ void CLogWindow::OnClear(wxCommandEvent& WXUNUSED (event))
{
std::lock_guard<std::mutex> lk(m_LogSection);
int msgQueueSize = (int)msgQueue.size();
for (int i = 0; i < msgQueueSize; i++)
while (!msgQueue.empty())
msgQueue.pop();
}
@ -280,10 +279,11 @@ void CLogWindow::OnWrapLineCheck(wxCommandEvent& event)
void CLogWindow::OnLogTimer(wxTimerEvent& WXUNUSED(event))
{
if (!m_LogAccess) return;
if (m_ignoreLogTimer) return;
if (!m_LogAccess || m_ignoreLogTimer)
return;
UpdateLog();
// Scroll to the last line
if (!msgQueue.empty())
{
@ -294,19 +294,16 @@ void CLogWindow::OnLogTimer(wxTimerEvent& WXUNUSED(event))
void CLogWindow::UpdateLog()
{
if (!m_LogAccess) return;
if (!m_Log) return;
if (!m_LogAccess || !m_Log)
return;
// m_LogTimer->Stop();
// instead of stopping the timer, let's simply ignore its calls during UpdateLog,
// because repeatedly stopping and starting a timer churns memory (and potentially leaks it).
m_ignoreLogTimer = true;
if (!msgQueue.empty())
{
std::lock_guard<std::mutex> lk(m_LogSection);
int msgQueueSize = (int)msgQueue.size();
for (int i = 0; i < msgQueueSize; i++)
while (!msgQueue.empty())
{
switch (msgQueue.front().first)
{
@ -334,18 +331,18 @@ void CLogWindow::UpdateLog()
m_Log->SetDefaultStyle(wxTextAttr(*wxWHITE));
break;
}
if (msgQueue.front().second.size())
{
int j = m_Log->GetLastPosition();
int i = m_Log->GetLastPosition();
m_Log->AppendText(msgQueue.front().second);
// White timestamp
m_Log->SetStyle(j, j + 9, wxTextAttr(*wxWHITE));
m_Log->SetStyle(i, i + 9, wxTextAttr(*wxWHITE));
}
msgQueue.pop();
}
} // unlock log
// m_LogTimer->Start(UPDATETIME);
m_ignoreLogTimer = false;
}